Integrand size = 20, antiderivative size = 120 \[ \int \frac {(a+b x)^2 (A+B x)}{(d+e x)^8} \, dx=\frac {(b d-a e)^2 (B d-A e)}{7 e^4 (d+e x)^7}-\frac {(b d-a e) (3 b B d-2 A b e-a B e)}{6 e^4 (d+e x)^6}+\frac {b (3 b B d-A b e-2 a B e)}{5 e^4 (d+e x)^5}-\frac {b^2 B}{4 e^4 (d+e x)^4} \]
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Time = 0.05 (sec) , antiderivative size = 120, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {78} \[ \int \frac {(a+b x)^2 (A+B x)}{(d+e x)^8} \, dx=\frac {b (-2 a B e-A b e+3 b B d)}{5 e^4 (d+e x)^5}-\frac {(b d-a e) (-a B e-2 A b e+3 b B d)}{6 e^4 (d+e x)^6}+\frac {(b d-a e)^2 (B d-A e)}{7 e^4 (d+e x)^7}-\frac {b^2 B}{4 e^4 (d+e x)^4} \]
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Rule 78
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {(-b d+a e)^2 (-B d+A e)}{e^3 (d+e x)^8}+\frac {(-b d+a e) (-3 b B d+2 A b e+a B e)}{e^3 (d+e x)^7}+\frac {b (-3 b B d+A b e+2 a B e)}{e^3 (d+e x)^6}+\frac {b^2 B}{e^3 (d+e x)^5}\right ) \, dx \\ & = \frac {(b d-a e)^2 (B d-A e)}{7 e^4 (d+e x)^7}-\frac {(b d-a e) (3 b B d-2 A b e-a B e)}{6 e^4 (d+e x)^6}+\frac {b (3 b B d-A b e-2 a B e)}{5 e^4 (d+e x)^5}-\frac {b^2 B}{4 e^4 (d+e x)^4} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.08 \[ \int \frac {(a+b x)^2 (A+B x)}{(d+e x)^8} \, dx=-\frac {10 a^2 e^2 (6 A e+B (d+7 e x))+4 a b e \left (5 A e (d+7 e x)+2 B \left (d^2+7 d e x+21 e^2 x^2\right )\right )+b^2 \left (4 A e \left (d^2+7 d e x+21 e^2 x^2\right )+3 B \left (d^3+7 d^2 e x+21 d e^2 x^2+35 e^3 x^3\right )\right )}{420 e^4 (d+e x)^7} \]
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Time = 0.68 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.31
method | result | size |
risch | \(\frac {-\frac {b^{2} B \,x^{3}}{4 e}-\frac {b \left (4 A b e +8 B a e +3 B b d \right ) x^{2}}{20 e^{2}}-\frac {\left (20 A a b \,e^{2}+4 A \,b^{2} d e +10 B \,a^{2} e^{2}+8 B a b d e +3 b^{2} B \,d^{2}\right ) x}{60 e^{3}}-\frac {60 a^{2} A \,e^{3}+20 A a b d \,e^{2}+4 A \,b^{2} d^{2} e +10 B \,a^{2} d \,e^{2}+8 B a b \,d^{2} e +3 b^{2} B \,d^{3}}{420 e^{4}}}{\left (e x +d \right )^{7}}\) | \(157\) |
default | \(-\frac {a^{2} A \,e^{3}-2 A a b d \,e^{2}+A \,b^{2} d^{2} e -B \,a^{2} d \,e^{2}+2 B a b \,d^{2} e -b^{2} B \,d^{3}}{7 e^{4} \left (e x +d \right )^{7}}-\frac {b \left (A b e +2 B a e -3 B b d \right )}{5 e^{4} \left (e x +d \right )^{5}}-\frac {2 A a b \,e^{2}-2 A \,b^{2} d e +B \,a^{2} e^{2}-4 B a b d e +3 b^{2} B \,d^{2}}{6 e^{4} \left (e x +d \right )^{6}}-\frac {b^{2} B}{4 e^{4} \left (e x +d \right )^{4}}\) | \(166\) |
gosper | \(-\frac {105 b^{2} B \,x^{3} e^{3}+84 A \,x^{2} b^{2} e^{3}+168 B \,x^{2} a b \,e^{3}+63 B \,x^{2} b^{2} d \,e^{2}+140 A x a b \,e^{3}+28 A x \,b^{2} d \,e^{2}+70 B x \,a^{2} e^{3}+56 B x a b d \,e^{2}+21 B x \,b^{2} d^{2} e +60 a^{2} A \,e^{3}+20 A a b d \,e^{2}+4 A \,b^{2} d^{2} e +10 B \,a^{2} d \,e^{2}+8 B a b \,d^{2} e +3 b^{2} B \,d^{3}}{420 e^{4} \left (e x +d \right )^{7}}\) | \(169\) |
parallelrisch | \(-\frac {105 b^{2} B \,x^{3} e^{6}+84 A \,b^{2} e^{6} x^{2}+168 B a b \,e^{6} x^{2}+63 B \,b^{2} d \,e^{5} x^{2}+140 A a b \,e^{6} x +28 A \,b^{2} d \,e^{5} x +70 B \,a^{2} e^{6} x +56 B a b d \,e^{5} x +21 B \,b^{2} d^{2} e^{4} x +60 a^{2} A \,e^{6}+20 A a b d \,e^{5}+4 A \,b^{2} d^{2} e^{4}+10 B \,a^{2} d \,e^{5}+8 B a b \,d^{2} e^{4}+3 B \,b^{2} d^{3} e^{3}}{420 e^{7} \left (e x +d \right )^{7}}\) | \(178\) |
norman | \(\frac {-\frac {b^{2} B \,x^{3}}{4 e}-\frac {\left (4 A \,b^{2} e^{4}+8 B a b \,e^{4}+3 b^{2} B d \,e^{3}\right ) x^{2}}{20 e^{5}}-\frac {\left (20 a b A \,e^{5}+4 A \,b^{2} d \,e^{4}+10 a^{2} B \,e^{5}+8 B a b d \,e^{4}+3 B \,b^{2} d^{2} e^{3}\right ) x}{60 e^{6}}-\frac {60 a^{2} A \,e^{6}+20 A a b d \,e^{5}+4 A \,b^{2} d^{2} e^{4}+10 B \,a^{2} d \,e^{5}+8 B a b \,d^{2} e^{4}+3 B \,b^{2} d^{3} e^{3}}{420 e^{7}}}{\left (e x +d \right )^{7}}\) | \(182\) |
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Leaf count of result is larger than twice the leaf count of optimal. 225 vs. \(2 (112) = 224\).
Time = 0.22 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.88 \[ \int \frac {(a+b x)^2 (A+B x)}{(d+e x)^8} \, dx=-\frac {105 \, B b^{2} e^{3} x^{3} + 3 \, B b^{2} d^{3} + 60 \, A a^{2} e^{3} + 4 \, {\left (2 \, B a b + A b^{2}\right )} d^{2} e + 10 \, {\left (B a^{2} + 2 \, A a b\right )} d e^{2} + 21 \, {\left (3 \, B b^{2} d e^{2} + 4 \, {\left (2 \, B a b + A b^{2}\right )} e^{3}\right )} x^{2} + 7 \, {\left (3 \, B b^{2} d^{2} e + 4 \, {\left (2 \, B a b + A b^{2}\right )} d e^{2} + 10 \, {\left (B a^{2} + 2 \, A a b\right )} e^{3}\right )} x}{420 \, {\left (e^{11} x^{7} + 7 \, d e^{10} x^{6} + 21 \, d^{2} e^{9} x^{5} + 35 \, d^{3} e^{8} x^{4} + 35 \, d^{4} e^{7} x^{3} + 21 \, d^{5} e^{6} x^{2} + 7 \, d^{6} e^{5} x + d^{7} e^{4}\right )}} \]
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Timed out. \[ \int \frac {(a+b x)^2 (A+B x)}{(d+e x)^8} \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 225 vs. \(2 (112) = 224\).
Time = 0.22 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.88 \[ \int \frac {(a+b x)^2 (A+B x)}{(d+e x)^8} \, dx=-\frac {105 \, B b^{2} e^{3} x^{3} + 3 \, B b^{2} d^{3} + 60 \, A a^{2} e^{3} + 4 \, {\left (2 \, B a b + A b^{2}\right )} d^{2} e + 10 \, {\left (B a^{2} + 2 \, A a b\right )} d e^{2} + 21 \, {\left (3 \, B b^{2} d e^{2} + 4 \, {\left (2 \, B a b + A b^{2}\right )} e^{3}\right )} x^{2} + 7 \, {\left (3 \, B b^{2} d^{2} e + 4 \, {\left (2 \, B a b + A b^{2}\right )} d e^{2} + 10 \, {\left (B a^{2} + 2 \, A a b\right )} e^{3}\right )} x}{420 \, {\left (e^{11} x^{7} + 7 \, d e^{10} x^{6} + 21 \, d^{2} e^{9} x^{5} + 35 \, d^{3} e^{8} x^{4} + 35 \, d^{4} e^{7} x^{3} + 21 \, d^{5} e^{6} x^{2} + 7 \, d^{6} e^{5} x + d^{7} e^{4}\right )}} \]
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Time = 0.29 (sec) , antiderivative size = 168, normalized size of antiderivative = 1.40 \[ \int \frac {(a+b x)^2 (A+B x)}{(d+e x)^8} \, dx=-\frac {105 \, B b^{2} e^{3} x^{3} + 63 \, B b^{2} d e^{2} x^{2} + 168 \, B a b e^{3} x^{2} + 84 \, A b^{2} e^{3} x^{2} + 21 \, B b^{2} d^{2} e x + 56 \, B a b d e^{2} x + 28 \, A b^{2} d e^{2} x + 70 \, B a^{2} e^{3} x + 140 \, A a b e^{3} x + 3 \, B b^{2} d^{3} + 8 \, B a b d^{2} e + 4 \, A b^{2} d^{2} e + 10 \, B a^{2} d e^{2} + 20 \, A a b d e^{2} + 60 \, A a^{2} e^{3}}{420 \, {\left (e x + d\right )}^{7} e^{4}} \]
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Time = 1.29 (sec) , antiderivative size = 223, normalized size of antiderivative = 1.86 \[ \int \frac {(a+b x)^2 (A+B x)}{(d+e x)^8} \, dx=-\frac {\frac {10\,B\,a^2\,d\,e^2+60\,A\,a^2\,e^3+8\,B\,a\,b\,d^2\,e+20\,A\,a\,b\,d\,e^2+3\,B\,b^2\,d^3+4\,A\,b^2\,d^2\,e}{420\,e^4}+\frac {x\,\left (10\,B\,a^2\,e^2+8\,B\,a\,b\,d\,e+20\,A\,a\,b\,e^2+3\,B\,b^2\,d^2+4\,A\,b^2\,d\,e\right )}{60\,e^3}+\frac {b\,x^2\,\left (4\,A\,b\,e+8\,B\,a\,e+3\,B\,b\,d\right )}{20\,e^2}+\frac {B\,b^2\,x^3}{4\,e}}{d^7+7\,d^6\,e\,x+21\,d^5\,e^2\,x^2+35\,d^4\,e^3\,x^3+35\,d^3\,e^4\,x^4+21\,d^2\,e^5\,x^5+7\,d\,e^6\,x^6+e^7\,x^7} \]
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